1/2y^2-4y=0

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Solution for 1/2y^2-4y=0 equation: 


y in (-oo:+oo)

(1/2)*y^2-(4*y) = 0

(1/2)*y^2-4*y = 0

1/2*y^2-4*y = 0

DELTA = (-4)^2-(0*1/2*4)

DELTA = 16

DELTA > 0

y = (16^(1/2)+4)/(1/2*2) or y = (4-16^(1/2))/(1/2*2)

y = 8 or y = 0

y in { 0, 8 }

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